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Gauss

The contributions of Carl Friedrich Gauss (1777-1855) are found in two brief unpublished letters and notes. He begins with a different definition of parallel.

Definition: Given a line tex2html_wrap_inline12754 and a point P not on tex2html_wrap_inline12754, let AP be the perpendicular from P to tex2html_wrap_inline12754. A line tex2html_wrap_inline15614 is parallel to tex2html_wrap_inline12754 through P if for any line tex2html_wrap_inline15620 with S in the interior of tex2html_wrap_inline15624 and tex2html_wrap_inline15626, it follows that tex2html_wrap_inline15620 intersects tex2html_wrap_inline12754.

So it would seem that as we consider the set of lines through the point P sweeping up from tex2html_wrap_inline14614, the parallel tex2html_wrap_inline15614 is the first line not meeting tex2html_wrap_inline12754. Unless we assume Euclid's Postulate V, we do not know that this line is unique. Thus it may depend on the side of tex2html_wrap_inline14614 we choose. Therefore, we speak of parallel lines in a direction. These lines will be called nonintersecting lines to distinguish them from parallel lines.

Theorem 11.8: In a given direction, being parallel is an equivalence relation.

Proof: We need to show three things:

    1. First we must show that it is well-defined: that is, if tex2html_wrap_inline15614 is parallel to tex2html_wrap_inline12754 and S is any point between P and Q, then tex2html_wrap_inline15652 is parallel to tex2html_wrap_inline12754.
    2. We must also show that the relation is reflexive; that is if tex2html_wrap_inline15614 is parallel to tex2html_wrap_inline12754 in a gven direction then tex2html_wrap_inline12754 is parallel to tex2html_wrap_inline15614 in the same direction..
    3. We must show that the relation is transitive; if tex2html_wrap_inline12754 is parallel to tex2html_wrap_inline15614 in a given direction and tex2html_wrap_inline15614 is parallel to tex2html_wrap_inline15670 in the same direction, then tex2html_wrap_inline12754 is parallel to tex2html_wrap_inline15670 in that direction.
To begin
    1. Let tex2html_wrap_inline15676 and consider any line through S, tex2html_wrap_inline15680, such that C is interior to tex2html_wrap_inline15624 and tex2html_wrap_inline15686. Construct tex2html_wrap_inline15688. By our assumption tex2html_wrap_inline15688 intersects tex2html_wrap_inline12754. Thus, tex2html_wrap_inline15680 has entered a triangle, so by Pasch's Theorem it must intersect tex2html_wrap_inline12754.
    2. Let R be the foot of A in tex2html_wrap_inline15614. Let S be a point in the interiors of tex2html_wrap_inline15706 and tex2html_wrap_inline15708, and construct the line tex2html_wrap_inline15710.

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Next: Hyperbolic Geometry Up: The Work of Saccheri Previous: Saccheri

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